区域内点的个数
目录
Problem Description
X晚上睡不着的时候不喜欢玩手机,也不喜欢打游戏,他喜欢数星星。
Input
多组输入。
每组先输入一个整数N(N <= 10000),接着输入两个点代表矩形的左下点B(x,y)和右上点T(x,y),然后输入N个(X,Y)代表N颗星星。问有多少颗星星在窗子内部,在窗边上的不计。
Output
输出一个整数,代表有多少颗星星在窗子内部。
Example Input
3 0 1 3 4 1 1 2 2 3 3
Example Output
1
Hint
import java.util.Scanner;
public class Main {
public static void main(String[] args) {
Scanner sc = new Scanner(System.in);
while (sc.hasNext()) {
int count = sc.nextInt();
Point[] points = new Point[count];
int px1 = sc.nextInt();
int py1 = sc.nextInt();
int px2 = sc.nextInt();
int py2 = sc.nextInt();
Point p1 = new Point(px1, py1);
Point p2 = new Point(px2, py2);
int resultCount = 0;
for (int i = 0; i < count; i++) {
points[i] = new Point(sc.nextInt(), sc.nextInt());
if (points[i].inRect(p1, p2)) {
resultCount++;
}
}
System.out.println(resultCount);
}
sc.close();
}
}
class Point {
int x;
int y;
public Point(int x, int y) {
this.x = x;
this.y = y;
}
public boolean inRect(Point p1, Point p2) {
boolean flag = false;
if (x > p1.x && x < p2.x && y > p1.y && y < p2.y) {
flag = true;
}
return flag;
}
}
转载自:https://blog.csdn.net/rchg150638/article/details/70215460