python遍历一个目录，输出所有的文件名

python 获取一个文件夹内(包括子文件夹)所有文件的名字和路径

import os
dir = "e:\\"
for root, dirs, files in os.walk(dir):
    for file in files:
        print os.path.join(root,file)

或：

import os
path = r'e:\case'
fns = [os.path.join(root,fn) for root, dirs, files in os.walk(path) for fn in files]
for f in fns:
    print(f)
print(len(fns))

#coding=utf-8
import os

def GetFileList(dir, fileList):
    newDir = dir
    if os.path.isfile(dir):
        fileList.append(dir.decode('gbk'))
    elif os.path.isdir(dir):  
        for s in os.listdir(dir):
            #如果需要忽略某些文件夹，使用以下代码
            #if s == "xxx":
                #continue
            newDir=os.path.join(dir,s)
            GetFileList(newDir, fileList)  
    return fileList

list = GetFileList('D:\\workspace\\PyDemo\\fas', [])
for e in list:
    print e

转载自：https://blog.csdn.net/Thinking_boy1992/article/details/70239367